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(B) The feasible region is determined by the constraints $2x + y \geq 3$,$x + 2y \geq 6$,$x \geq 0$,and $y \geq 0$.First,we find the intersection poin

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$6$

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(B) The feasible region is determined by the constraints $2x + y \geq 3$,$x + 2y \geq 6$,$x \geq 0$,and $y \geq 0$.First,we find the intersection points of the lines:$1$. For $2x + y = 3$,the intercepts are $(1.5, 0)$ and $(0, 3)$.$2$. For $x + 2y = 6$,the intercepts are $(6, 0)$ and $(0, 3)$.The feasible region is the unbounded region in the first quadrant above both lines. The corner points of the feasible region are $(6, 0)$ and $(0, 3)$.We evaluate $Z = x + 2y$ at these corner points:Corner Point$Z = x + 2y$$(6, 0)$$6 + 2(0) = 6$$(0, 3)$$0 + 2(3) = 6$Since the value of $Z$ is $6$ at both corner points,the minimum value of $Z$ is $6$. This minimum value occurs at every point on the line segment connecting $(6, 0)$ and $(0, 3)$.

Solve the following Linear Programming Problem graphically:
Minimise $Z = x + 2y$
subject to the constraints:
$2x + y \geq 3$
$x + 2y \geq 6$
$x, y \geq 0$

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Solve the following Linear Programming Problem graphically:Minimise $Z = x + 2y$subject to the constraints:$2x + y \geq 3$$x + 2y \geq 6$$x, y \geq 0$